To run several shell script processes, but don't want the hassle of maintaining multiple scripts? Yes, you can put them into functions within ONE script. It's elegant, beautiful, and much easier to read and maintain.
Here is an example:
1 #!/bin/bash
2 #
3 # Test shell script with background function(s)
4 #
5
6 func1 ()
7 {
8 cat /dev/null > func1.txt
9 i=0
10 while [ $i -le 100 ];
11 do
12 echo $i >> func1.txt
13 echo "From func1: $i"
14 sleep 1
15 (( i = i + 1 ))
16 done
17 }
18
19 func2 ()
20 {
21 cat /dev/null > func2.txt
22 j=0
23 while [ $j -le 10 ];
24 do
25 echo $j >> func2.txt
26 echo "From func2: $j"
27 sleep 6
28 (( j = j + 1 ))
29 done
30 }
31
32 func1 &
33 x=$!
34 echo "func1 PID: $x"
35
36 func2 &
37 y=$!
38 echo "func2 PID: $y"
39
40 echo "Waiting for both function finishing..."
41 wait $y
42 wait $x
43
44 echo "Both function finishing, quit the main script."
As in shell prompt, we can add an '&' after the name of the calling functions (line 32,36), to put them into background. In other words, the shell duplicates the original processes into several processes, as below:
debian-lenny:~# ps -ef | grep test
user 3517 3337 0 03:06 pts/0 00:00:00 /bin/bash ./test-bg.sh
user 3518 3517 0 03:06 pts/0 00:00:00 /bin/bash ./test-bg.sh
user 3521 3517 0 03:06 pts/0 00:00:00 /bin/bash ./test-bg.sh
Where 3517 is the parent process, and 3518 and 3521 are the duplicates.
In line 33 and 37, use the '$!' to get their Process IDs (PID), that are, 3518 and 3521 respectively.
Finally, use the 'wait' function (in line 41 and 42) for waiting them both finish, before printing the final message and exit.
This is quite useful in doing some tasks, like running multiple instances of file copy - that speeds things up.